100=0.0104x^2-4.49628x+564.482614

Solution for 100=0.0104x^2-4.49628x+564.482614 equation:

100=0.0104x^2-4.49628x+564.482614

We move all terms to the left:

100-(0.0104x^2-4.49628x+564.482614)=0

We get rid of parentheses

-0.0104x^2+4.49628x-564.482614+100=0

We add all the numbers together, and all the variables

-0.0104x^2+4.49628x-464.482614=0

a = -0.0104; b = 4.49628; c = -464.482614;
Δ = b2-4ac
Δ = 4.496282-4·(-0.0104)·(-464.482614)
Δ = 0.894057096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.49628)-\sqrt{0.894057096}}{2*-0.0104}=\frac{-4.49628-\sqrt{0.894057096}}{-0.0208}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.49628)+\sqrt{0.894057096}}{2*-0.0104}=\frac{-4.49628+\sqrt{0.894057096}}{-0.0208}
$